11 references to EachKeyword
Microsoft.CodeAnalysis.VisualBasic (7)
Generated\Syntax.xml.Main.Generated.vb (2)
3521Dim newEachKeyword = DirectCast(VisitToken(node.EachKeyword).Node, InternalSyntax.KeywordSyntax) 3522If node.EachKeyword.Node IsNot newEachKeyword Then anyChanges = True
Generated\Syntax.xml.Syntax.Generated.vb (5)
19504return Update(forKeyword, Me.EachKeyword, Me.ControlVariable, Me.InKeyword, Me.Expression) 19551return Update(Me.ForKeyword, Me.EachKeyword, controlVariable, Me.InKeyword, Me.Expression) 19569return Update(Me.ForKeyword, Me.EachKeyword, Me.ControlVariable, inKeyword, Me.Expression) 19587return Update(Me.ForKeyword, Me.EachKeyword, Me.ControlVariable, Me.InKeyword, expression) 19641If forKeyword <> Me.ForKeyword OrElse eachKeyword <> Me.EachKeyword OrElse controlVariable IsNot Me.ControlVariable OrElse inKeyword <> Me.InKeyword OrElse expression IsNot Me.Expression Then
Microsoft.CodeAnalysis.VisualBasic.Features (1)
Highlighting\KeywordHighlighters\ForLoopBlockHighlighter.vb (1)
38highlights.Add(TextSpan.FromBounds(.ForKeyword.SpanStart, .EachKeyword.Span.End))
Microsoft.CodeAnalysis.VisualBasic.Syntax.UnitTests (2)
Generated\Syntax.Test.xml.Generated.vb (2)
20122Assert.NotNull(objectUnderTest.eachKeyword) 20126Dim withObj = objectUnderTest.WithForKeyword(objectUnderTest.ForKeyword).WithEachKeyword(objectUnderTest.EachKeyword).WithControlVariable(objectUnderTest.ControlVariable).WithInKeyword(objectUnderTest.InKeyword).WithExpression(objectUnderTest.Expression)
Microsoft.VisualStudio.LanguageServices.VisualBasic (1)
Help\VisualBasicHelpContextService.Visitor.vb (1)
255ElseIf node.EachKeyword.Span.IntersectsWith(_span) Then