6 references to IsPartitionClause
Microsoft.CodeAnalysis.VisualBasic (3)
Generated\Syntax.xml.Internal.Generated.vb (2)
52234Debug.Assert(SyntaxFacts.IsPartitionClause(kind)) 64312Debug.Assert(SyntaxFacts.IsPartitionClause(kind))
Generated\Syntax.xml.Main.Generated.vb (1)
39070If Not SyntaxFacts.IsPartitionClause(kind) Then
Microsoft.CodeAnalysis.VisualBasic.Syntax.UnitTests (3)
Syntax\SyntaxFactsTest.vb (3)
710Assert.True(SyntaxFacts.IsPartitionClause(item)) 712Assert.False(SyntaxFacts.IsPartitionClause(SyntaxKind.ExitKeyword)) 713Assert.False(SyntaxFacts.IsPartitionClause(SyntaxKind.None))