13 references to SubKeyword
Microsoft.CodeAnalysis.VisualBasic (9)
Generated\Syntax.xml.Main.Generated.vb (2)
2150
Dim newSubKeyword = DirectCast(VisitToken(node.
SubKeyword
).Node, InternalSyntax.KeywordSyntax)
2151
If node.
SubKeyword
.Node IsNot newSubKeyword Then anyChanges = True
Generated\Syntax.xml.Syntax.Generated.vb (5)
7018
return Update(attributeLists, Me.Modifiers, Me.
SubKeyword
, Me.NewKeyword, Me.ParameterList)
7062
return Update(Me.AttributeLists, modifiers, Me.
SubKeyword
, Me.NewKeyword, Me.ParameterList)
7106
return Update(Me.AttributeLists, Me.Modifiers, Me.
SubKeyword
, newKeyword, Me.ParameterList)
7136
return Update(Me.AttributeLists, Me.Modifiers, Me.
SubKeyword
, Me.NewKeyword, parameterList)
7199
If attributeLists <> Me.AttributeLists OrElse modifiers <> Me.Modifiers OrElse subKeyword <> Me.
SubKeyword
OrElse newKeyword <> Me.NewKeyword OrElse parameterList IsNot Me.ParameterList Then
Lowering\Instrumentation\CodeCoverageInstrumenter.vb (1)
536
Return SkipAttributes(syntax, constructorSyntax.AttributeLists, constructorSyntax.Modifiers, constructorSyntax.
SubKeyword
)
Syntax\MethodBaseSyntax.vb (1)
153
Return
SubKeyword
Microsoft.CodeAnalysis.VisualBasic.CodeStyle (1)
StatementSyntaxExtensions.vb (1)
358
Return DirectCast(DirectCast(member, ConstructorBlockSyntax).BlockStatement, SubNewStatementSyntax).
SubKeyword
Microsoft.CodeAnalysis.VisualBasic.Syntax.UnitTests (2)
Generated\Syntax.Test.xml.Generated.vb (2)
19061
Assert.NotNull(objectUnderTest.
subKeyword
)
19063
Dim withObj = objectUnderTest.WithAttributeLists(objectUnderTest.AttributeLists).WithModifiers(objectUnderTest.Modifiers).WithSubKeyword(objectUnderTest.
SubKeyword
).WithNewKeyword(objectUnderTest.NewKeyword).WithParameterList(objectUnderTest.ParameterList)
Microsoft.CodeAnalysis.VisualBasic.Workspaces (1)
StatementSyntaxExtensions.vb (1)
358
Return DirectCast(DirectCast(member, ConstructorBlockSyntax).BlockStatement, SubNewStatementSyntax).
SubKeyword