11 references to InKeyword
Microsoft.CodeAnalysis.VisualBasic (6)
Generated\Syntax.xml.Main.Generated.vb (2)
4368Dim newInKeyword = DirectCast(VisitToken(node.InKeyword).Node, InternalSyntax.KeywordSyntax) 4369If node.InKeyword.Node IsNot newInKeyword Then anyChanges = True
Generated\Syntax.xml.Syntax.Generated.vb (4)
27229return Update(identifier, Me.AsClause, Me.InKeyword, Me.Expression) 27250return Update(Me.Identifier, asClause, Me.InKeyword, Me.Expression) 27286return Update(Me.Identifier, Me.AsClause, Me.InKeyword, expression) 27341If identifier IsNot Me.Identifier OrElse asClause IsNot Me.AsClause OrElse inKeyword <> Me.InKeyword OrElse expression IsNot Me.Expression Then
Microsoft.CodeAnalysis.VisualBasic.CodeStyle.Fixes (1)
SyntaxTreeExtensions.vb (1)
387targetToken.IsChildToken(Of CollectionRangeVariableSyntax)(Function(collectionRange) collectionRange.InKeyword) OrElse
Microsoft.CodeAnalysis.VisualBasic.Syntax.UnitTests (2)
Generated\Syntax.Test.xml.Generated.vb (2)
21078Assert.NotNull(objectUnderTest.inKeyword) 21080Dim withObj = objectUnderTest.WithIdentifier(objectUnderTest.Identifier).WithAsClause(objectUnderTest.AsClause).WithInKeyword(objectUnderTest.InKeyword).WithExpression(objectUnderTest.Expression)
Microsoft.CodeAnalysis.VisualBasic.Workspaces (1)
J\s\src\Workspaces\SharedUtilitiesAndExtensions\Workspace\VisualBasic\Extensions\ContextQuery\SyntaxTreeExtensions.vb\SyntaxTreeExtensions.vb (1)
387targetToken.IsChildToken(Of CollectionRangeVariableSyntax)(Function(collectionRange) collectionRange.InKeyword) OrElse
Microsoft.VisualStudio.LanguageServices.VisualBasic (1)
Help\VisualBasicHelpContextService.Visitor.vb (1)
920If node.InKeyword.Span.IntersectsWith(_span) Then