10 references to OnKeyword
Microsoft.CodeAnalysis.VisualBasic (8)
Generated\Syntax.xml.Main.Generated.vb (2)
4619
Dim newOnKeyword = DirectCast(VisitToken(node.
OnKeyword
).Node, InternalSyntax.KeywordSyntax)
4620
If node.
OnKeyword
.Node IsNot newOnKeyword Then anyChanges = True
Generated\Syntax.xml.Syntax.Generated.vb (6)
29463
return Update(joinKeyword, Me.JoinedVariables, Me.AdditionalJoins, Me.
OnKeyword
, Me.JoinConditions)
29489
return Update(Me.JoinKeyword, joinedVariables, Me.AdditionalJoins, Me.
OnKeyword
, Me.JoinConditions)
29527
return Update(Me.JoinKeyword, Me.JoinedVariables, additionalJoins, Me.
OnKeyword
, Me.JoinConditions)
29548
Return Me.
OnKeyword
29588
return Update(Me.JoinKeyword, Me.JoinedVariables, Me.AdditionalJoins, Me.
OnKeyword
, joinConditions)
29654
If joinKeyword <> Me.JoinKeyword OrElse joinedVariables <> Me.JoinedVariables OrElse additionalJoins <> Me.AdditionalJoins OrElse onKeyword <> Me.
OnKeyword
OrElse joinConditions <> Me.JoinConditions Then
Microsoft.CodeAnalysis.VisualBasic.Syntax.UnitTests (2)
Generated\Syntax.Test.xml.Generated.vb (2)
21236
Assert.NotNull(objectUnderTest.
onKeyword
)
21238
Dim withObj = objectUnderTest.WithJoinKeyword(objectUnderTest.JoinKeyword).WithJoinedVariables(objectUnderTest.JoinedVariables).WithAdditionalJoins(objectUnderTest.AdditionalJoins).WithOnKeyword(objectUnderTest.
OnKeyword
).WithJoinConditions(objectUnderTest.JoinConditions)