11 references to XmlKeyword
Microsoft.CodeAnalysis.VisualBasic (8)
Generated\Syntax.xml.Main.Generated.vb (2)
4729
Dim newXmlKeyword = DirectCast(VisitToken(node.
XmlKeyword
).Node, InternalSyntax.KeywordSyntax)
4730
If node.
XmlKeyword
.Node IsNot newXmlKeyword Then anyChanges = True
Generated\Syntax.xml.Syntax.Generated.vb (6)
30602
return Update(lessThanQuestionToken, Me.
XmlKeyword
, Me.Version, Me.Encoding, Me.Standalone, Me.QuestionGreaterThanToken)
30632
return Update(Me.LessThanQuestionToken, Me.
XmlKeyword
, version, Me.Encoding, Me.Standalone, Me.QuestionGreaterThanToken)
30650
return Update(Me.LessThanQuestionToken, Me.
XmlKeyword
, Me.Version, encoding, Me.Standalone, Me.QuestionGreaterThanToken)
30668
return Update(Me.LessThanQuestionToken, Me.
XmlKeyword
, Me.Version, Me.Encoding, standalone, Me.QuestionGreaterThanToken)
30683
return Update(Me.LessThanQuestionToken, Me.
XmlKeyword
, Me.Version, Me.Encoding, Me.Standalone, questionGreaterThanToken)
30744
If lessThanQuestionToken <> Me.LessThanQuestionToken OrElse xmlKeyword <> Me.
XmlKeyword
OrElse version IsNot Me.Version OrElse encoding IsNot Me.Encoding OrElse standalone IsNot Me.Standalone OrElse questionGreaterThanToken <> Me.QuestionGreaterThanToken Then
Microsoft.CodeAnalysis.VisualBasic.Syntax.UnitTests (2)
Generated\Syntax.Test.xml.Generated.vb (2)
21304
Assert.NotNull(objectUnderTest.
xmlKeyword
)
21307
Dim withObj = objectUnderTest.WithLessThanQuestionToken(objectUnderTest.LessThanQuestionToken).WithXmlKeyword(objectUnderTest.
XmlKeyword
).WithVersion(objectUnderTest.Version).WithEncoding(objectUnderTest.Encoding).WithStandalone(objectUnderTest.Standalone).WithQuestionGreaterThanToken(objectUnderTest.QuestionGreaterThanToken)
Microsoft.CodeAnalysis.VisualBasic.Workspaces (1)
Classification\Worker.XmlClassifier.vb (1)
203
AddTokenClassification(node.
XmlKeyword
, ClassificationTypeNames.XmlLiteralName)