12 references to CommaToken
Microsoft.CodeAnalysis.VisualBasic (9)
Generated\Syntax.xml.Main.Generated.vb (2)
4103
Dim newCommaToken = DirectCast(VisitToken(node.
CommaToken
).Node, InternalSyntax.PunctuationSyntax)
4104
If node.
CommaToken
.Node IsNot newCommaToken Then anyChanges = True
Generated\Syntax.xml.Syntax.Generated.vb (7)
24795
return Update(keyword, Me.OpenParenToken, Me.Expression, Me.
CommaToken
, Me.Type, Me.CloseParenToken)
24821
return Update(Me.Keyword, openParenToken, Me.Expression, Me.
CommaToken
, Me.Type, Me.CloseParenToken)
24847
return Update(Me.Keyword, Me.OpenParenToken, expression, Me.
CommaToken
, Me.Type, Me.CloseParenToken)
24860
Return Me.
CommaToken
24898
return Update(Me.Keyword, Me.OpenParenToken, Me.Expression, Me.
CommaToken
, type, Me.CloseParenToken)
24924
return Update(Me.Keyword, Me.OpenParenToken, Me.Expression, Me.
CommaToken
, Me.Type, closeParenToken)
24981
If keyword <> Me.Keyword OrElse openParenToken <> Me.OpenParenToken OrElse expression IsNot Me.Expression OrElse commaToken <> Me.
CommaToken
OrElse type IsNot Me.Type OrElse closeParenToken <> Me.CloseParenToken Then
Microsoft.CodeAnalysis.VisualBasic.Features (1)
ConvertCast\VisualBasicConvertTryCastToDirectCastCodeRefactoringProvider.vb (1)
36
fromExpression.
CommaToken
,
Microsoft.CodeAnalysis.VisualBasic.Syntax.UnitTests (2)
Generated\Syntax.Test.xml.Generated.vb (2)
20648
Assert.NotNull(objectUnderTest.
commaToken
)
20651
Dim withObj = objectUnderTest.WithKeyword(objectUnderTest.Keyword).WithOpenParenToken(objectUnderTest.OpenParenToken).WithExpression(objectUnderTest.Expression).WithCommaToken(objectUnderTest.
CommaToken
).WithType(objectUnderTest.Type).WithCloseParenToken(objectUnderTest.CloseParenToken)