37 references to JoinClause
Microsoft.CodeAnalysis.CSharp (16)
Binder\Binder.IdentifierUsedAsValueFinder.cs (1)
405case SyntaxKind.JoinClause:
Binder\Binder_Query.cs (2)
140case SyntaxKind.JoinClause: 341case SyntaxKind.JoinClause:
Binder\Binder_QueryErrors.cs (3)
138if (parent.Kind() == SyntaxKind.JoinClause) 154if (parent.Kind() == SyntaxKind.JoinClause) 170case SyntaxKind.JoinClause:
Binder\ExpressionVariableFinder.cs (1)
316if (clause.Kind() == SyntaxKind.JoinClause)
Binder\LocalBinderFactory.cs (1)
1004if (clause.Kind() == SyntaxKind.JoinClause)
Syntax\LambdaUtilities.cs (5)
29case SyntaxKind.JoinClause: 102case SyntaxKind.JoinClause: 167case SyntaxKind.JoinClause: 306case SyntaxKind.JoinClause: 377syntax.IsKind(SyntaxKind.JoinClause) ||
Syntax\SyntaxFacts.cs (1)
125case JoinClause:
Syntax\SyntaxNodeExtensions.cs (1)
39case SyntaxKind.JoinClause:
Syntax\SyntaxNormalizer.cs (1)
282(nextToken.IsKind(SyntaxKind.JoinKeyword) && nextToken.Parent.IsKind(SyntaxKind.JoinClause)) ||
Microsoft.CodeAnalysis.CSharp.CodeStyle (1)
ElasticTriviaFormattingRule.cs (1)
363(currentToken.Kind() == SyntaxKind.JoinKeyword && currentToken.Parent.IsKind(SyntaxKind.JoinClause)) ||
Microsoft.CodeAnalysis.CSharp.CodeStyle.Fixes (2)
J\s\src\Workspaces\SharedUtilitiesAndExtensions\Workspace\CSharp\Extensions\ContextQuery\SyntaxTreeExtensions.cs\SyntaxTreeExtensions.cs (2)
2557SyntaxKind.JoinClause)) 2568if (token.Parent.IsKind(SyntaxKind.JoinClause))
Microsoft.CodeAnalysis.CSharp.Features (12)
ConvertLinq\CSharpConvertLinqQueryToForEachProvider.cs (2)
156case SyntaxKind.JoinClause: 867case SyntaxKind.JoinClause:
EditAndContinue\BreakpointSpans.cs (1)
286case SyntaxKind.JoinClause:
EditAndContinue\CSharpEditAndContinueAnalyzer.cs (3)
1505case SyntaxKind.JoinClause: 1855case SyntaxKind.JoinClause: 2150case SyntaxKind.JoinClause:
EditAndContinue\SyntaxComparer.cs (1)
495case SyntaxKind.JoinClause:
LambdaUtilities.cs (5)
29case SyntaxKind.JoinClause: 102case SyntaxKind.JoinClause: 167case SyntaxKind.JoinClause: 306case SyntaxKind.JoinClause: 377syntax.IsKind(SyntaxKind.JoinClause) ||
Microsoft.CodeAnalysis.CSharp.Syntax.UnitTests (3)
Parsing\ExpressionParsingTests.cs (3)
2840Assert.Equal(SyntaxKind.JoinClause, qs.Body.Clauses[0].Kind()); 2897Assert.Equal(SyntaxKind.JoinClause, qs.Body.Clauses[0].Kind()); 2951Assert.Equal(SyntaxKind.JoinClause, qs.Body.Clauses[0].Kind());
Microsoft.CodeAnalysis.CSharp.Workspaces (3)
ElasticTriviaFormattingRule.cs (1)
363(currentToken.Kind() == SyntaxKind.JoinKeyword && currentToken.Parent.IsKind(SyntaxKind.JoinClause)) ||
J\s\src\Workspaces\SharedUtilitiesAndExtensions\Workspace\CSharp\Extensions\ContextQuery\SyntaxTreeExtensions.cs\SyntaxTreeExtensions.cs (2)
2557SyntaxKind.JoinClause)) 2568if (token.Parent.IsKind(SyntaxKind.JoinClause))